For this problem, we'll round an `int`

value up to the next multiple of 10 if its rightmost digit is 5 or more, so 15 rounds up to 20....

# X96: roundSum

For this problem, we'll round an `int`

value up to the next
multiple of 10 if its rightmost digit is 5 or more, so 15 rounds
up to 20. Alternately, round down to the previous multiple
of 10 if its rightmost digit is less than 5, so 12 rounds down
to 10. Given 3 `int`

s, `a`

, `b`

, and `c`

, return the sum of their
rounded values. To avoid code repetition, write a separate helper
`public int round10(int num)`

and call it 3 times. Write the
helper entirely below and at the same indent level as `roundSum()`

.

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